To calculate the storage required to record one hour of video from two cameras streaming at 6 Mbit/s each, we use the following steps:
* Total bitrate for both cameras: 6 Mbit/s×2=12 Mbit/s6 \text{ Mbit/s} \times 2 = 12 \text{ Mbit/s}6 Mbit
/s×2=12 Mbit/s
* Convert Mbit/s to Mbyte/s: 12 Mbit/s÷8=1.5 Mbyte/s12 \text{ Mbit/s} \div 8 = 1.5 \text{ Mbyte/s}
12 Mbit/s÷8=1.5 Mbyte/s
* Calculate the total data for one hour: 1.5 Mbyte/s×3600 seconds=5400 Mbytes1.5 \text{ Mbyte/s}
\times 3600 \text{ seconds} = 5400 \text{ Mbytes}1.5 Mbyte/s×3600 seconds=5400 Mbytes
* Convert Mbytes to Gbytes: 5400 Mbytes÷1024=5.27 Gbytes5400 \text{ Mbytes} \div 1024 = 5.27 \text { Gbytes}5400 Mbytes÷1024=5.27 Gbytes
Approximately, the storage required is 5.4 GB.
Reference: Axis Communications. "Calculating storage requirements." Axis Storage Calculation.