The command sequence uses a while loop to read the input from the echo command and assign the values to the variables a, b, and c. The read command reads one line of input at a time and splits it into words according to the IFS variable, which is a space by default. The first word is assigned to the first variable, the second word to the second variable, and so on. If there are more words than variables, the remaining words are assigned to the last variable. In this case, the input line has six words, so the read command assigns 1 to a, 2 to b, and 3 4 5
6 to c. Then, the echo command prints the result with the variables in reverse order, i.e., $c $b $a. Therefore, the output is result: 6 5 4 3 2 1. However, the answer choices only show the first three words of the output, so the correct answer is A. result: 6 5 4. References: [LPI 102-500 Exam Objectives], Topic 105.3: Customize and use the shell environment, Weight: 4. [LPI Linux Essentials Study Guide], Chapter 7: The Linux Operating System, Section 7.2: Shell Scripting.